The prime factors of N are both 2 mod 3, where N = 117968734185852909111122793179458044429748833609671492956099236663454458021167483523103665043186849896340566668709082216630299186083868726474403014230450576527498336056399517500373699648384503014218007972984281676376443077883955580519873153351211473492074726331214866950482499437571095445498914388647218496094203506927341398236714690311062488254644318997750013131645597009546941216705983462580669754031513
15
146Ṁ7582
resolved May 27
Resolved
NO
N is a number that I generated by multiplying together two large primes. N = 1 mod 3, so therefore the prime factors of N must either: - Both be 1 mod 3 (question resolves to no) - Both be 2 mod 3 (question resolves to yes)
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