How many prime factors does the 1801st Fibonacci number have?

Basic

10

Ṁ1602100

17%

2

17%

3

14%

4

52%

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1,000

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https://r-knott.surrey.ac.uk/Fibonacci/fibtable.html almost all of them have more than 3

@nanob0nus Indeed, the prime number theorem tells us that the density of primes goes like 1/log(n), and knth fibonacci number is divisible by the nth, so for any x, almost all Fibonacci numbers will have at least x factors.

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