How many prime factors does the 1801st Fibonacci number have?
Basic
10
Ṁ160
2100
17%
2
17%
3
14%
4
52%
Other

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Ṁ1,000
and
S3.00
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@nanob0nus (probably even the mathematical meaning of "almost all")

@nanob0nus Indeed, the prime number theorem tells us that the density of primes goes like 1/log(n), and knth fibonacci number is divisible by the nth, so for any x, almost all Fibonacci numbers will have at least x factors.

Bit more complicated here, though, since there is the bias of this being the smallest Fibonacci number that our efforts haven't factored.

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