@realazthat I am fascinated by your bets

@realazthat I have some sizeable limit orders open here still :)

Will this resolve yes for any kind of "breaking", even if AES256 would still be considered perfectly secure afterwards (for example if there was a way to break AES256 0.3% faster than bruteforce)?

@Primer for purposes of this market, "broken" means some entity could actually decrypt it in less than a decade with the amount of compute they have, without possessing the key, and without side-channel leaks.

AES has very little interesting mathematical structure. So there's little reason to think that any new "trick" will be discovered to crack it, save brute force