Basic
291
183k
Nov 6
52%
>50%, wins popular vote
26%
<50%, loses popular vote
22%
<50%, wins popular vote
0.1%
Exactly 50%

Get Ṁ1,000 play money
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bought Ṁ1,000 Exactly 50% YES

@AndrewG adding subsidy

>50%, wins popular vote
bought Ṁ1,000 >50%, wins popular vote YES

FWIW, nate silver's model has this at 38.3%

76% joint chance of winning the popular vote!

To clarify, this only resolves "exactly 50%" if she literally gets exactly half of the popular vote?

opened a Ṁ300 <50%, loses popular ... YES at 20% order

Oops, thanks!

as always, Cumulative Independent markets are the best for this kind of market

Exactly 50%

@AndrewG Are we rounding this to the nearest percentafg point? Because odds of a fair coin landing on heads exactly 75 million times out of 150 million is basically zero.

should be to the tenth imo, like this ^

but obviously up to Andrew, who currently holds 2000 NO on =50% so im guessing he won’t make it nearest percentage point.

No rounding!

In 50% of worlds there's an odd number of total votes, and in that case, a 75000000-75000001 result would still not count as exactly 50%

my two cents: for markets like this, you should just arbitrarily assign "exactly 50%" (which is so extremely unlikely) to some bucket

Wait, what does popular vote mean? If she has >50% has she not by definition wom the popular vote?

Yes; thus the absence of a ">50%, loses popular vote" option

Sorry for being dense. If she has less than 50% how can she win the popular vote?

bought Ṁ50 >50%, wins popular vote YES

@kevor RFK or others could pull a couple points from kamala/trump

Sorry yeah, of course, thanks :)