Will someone find the prime factorization of a 1000-digit random number in a week?
21
53
į¹€450
resolved Jan 6
Resolved
NO

Unlike the other prime factorization markets, which have been for semiprimes, this market will be for a completely random 1000-digit natural number, to be chosen by me using random.org one day after this market goes live.

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Another one is 15653718611933.

Current progress:

11 x 19853 x 15653718611933 x 318121106057622787788194362736808052194802936828152297069303172117856444015852742531290092225149516366447739264877856555276248778164698443650098053660129377111472196818374143498647923153083758833612654886850758039787723030644440235214407249293071523195465284627808070248397570720008573707872589664011073912682796447196950674342108714113601895549831323575420249670857737934023545851914051255341903370813482425889735368353156497719534651505251470774178968910630093151922245832437169848660148489240423251587220908969298795062392429717286034981680554326982537079383932032487818296136353252160682395247908416356961285523760168271155139554153485656099178485839074194340367576735443813473566874977550031517897571172962983559952969113776346451522997199264545107513530224523645827620072927124209093053389994246732864012542699025932963882701872736475041800765182540350625962434770836713300904819040290969680818146386411587613166360673571772409632085166590911683161448382937604719963106808999

(981 digits in the remaining number)

PS I don't understand how to format this thing, when I use asterisk, Manifold things it should be cursive

predicted NO

@wadimiusz Are you using cado-nfs, or something else? (Iā€™m clueless, just skimmed a little about tools.)

@yaboi69 Nah, just python's sympy module. It's sympy.ntheory.factorint function turns out to have a verbose argument, which is nice! It shows you the progress as it tries to decompose this number.

@yaboi69 but cado-nfs sounds better actually, let me try it

predicted NO

@wadimiusz I see there are few other implementations of that GNFS magic, not sure if they produce fun intermediate output, this one is apparently notable after RSA competitions

@yaboi69 Alright, I'll turn off sympy for the thousand-digit-number and try my luck with cado-nfs and the 250-digit one. (One thing I don't like i that it doesn't seem to show factors as it goes along, it just outputs all at the end of its work, which is lame I think)

@wadimiusz the number field sieve doesn't have any "as it goes along". It only gets one answer at the very end (and I recommend having some idea when "the end" is if you can so you don't say, try to run it on one core on a number that will take it 10 years).

@SeraphinaNix I see. I tried to understand the techinique, but it seems way above my current command of mathematics. The cado-nfs tool does indeed output an ETA as it progresses, and it doesn't look like it will be there even in a week, even for the 250-digit number. But the ETA seems to become shorter, so maybe the initial ETA was too pessimistic? Not sure

predicted YES

There is another factor. Current progress:

```11 * 19853 * 4979778278742921663569523683064842441809888042402056061436817915348285562703193717064237575286423042649176570859389702535247205911095490560595938322479985383222590457789841876477512723882163549997385215159176417316314715745234143021244247073047312259589408847924100507941081375248741813812258433309741510773581611645544634638632822338266555790881263236311311649314839489574095339306762802387989275785100639904840557872809869387621353644899479942147287526113429662902526786922882368509803299288846265247349330126231926483956403059044202011129357807962991077338624548366378826479327076767313267557218158610716800247070814308160341139504142405969426458042730449194243499027844150395410155425360023029909403968868106189670897290562465091122942681791899241648847364595246927000869394973671006629592168853400078023970673547298120746560236581522073707636772105972812767403812093143130681635662460334107112451222507696797104801339958113164121356550893187925098591020470095869197928713493134047233185067```

Among its factors is 11^1.

The remaining number is 98863538167883223786845753679886316997251707305808018987705146073409513276346504864876308582161356665714102461271463764432262778952978774099511163516195149813118088358501730773708060107232592958098088676555129412980796051690133441400762037141208290289628533857837167384154288542813271229614766676498298213387915735998997631480777421881605932116365719030488470173847508386514514771257161915808751092161603004030799595448894336952446733912189375291450099255929919097603864300779983662025124900781464903955626250996082436485986469931204542526951140561489261858403713158717718842094080455061470300813452102898560635305096876459907252642575739185711023471522327607853316186199789917800077815659672537212791396993938512183536323909536619454063781061614575644454566729309437241748260098412290494617293328246551749009889781934509591181460376852957729317712836619878251871267881485170573422512806825013028503494120445304512921621002188420647301291604882459876982327529392813291186478748979190239720423135151

Ok the link is here and the number is

1087498919
8467154616
5530329047
8749486969
7687803638
8820886475
6606807504
6460398115
5351363939
4403774923
3228551270
7398610140
8754890568
4827665150
9462279867
8146647944
2989719435
1903851078
8661179558
5225390789
7544210642
3542788756
5685914678
5540838240
8553291193
1859138724
3620884122
5697173970
9459835257
6243344148
1280347267
0730959889
7394628855
1640697665
2532800229
0933537317
1912322592
2516596624
8382878107
3896262013
7776330443
3879554993
7837706476
9140730340
8312820595
1091815229
1100736425
0730857982
0282276373
9085961139
4351188876
0956906801
3458511692
4324996779
6462546176
3818804424
4084474589
4907263034
8850056761
7330894797
3131884166
9883560656
4105897977
9068333131
0428212581
8674560368
6386478048
1976890958
0085597225
6397909340
7053669333
2363401889
9563004902
8139947015
9167776033
2089000234
0224038096
5923086108
2535195440
7902266107
1206923910
8787601279
6055029960
6414538253
5022494841
2028186607
7058394669
6336876307
6476408750
7514331353
8435324898
3496421378
3102407262
7120314207
6537070586
4680560282
3320946203
0512662387
7109263692
4654486661
predicted YES

@BoltonBailey As a number 1087498919846715461655303290478749486969768780363888208864756606807504646039811553513639394403774923322855127073986101408754890568482766515094622798678146647944298971943519038510788661179558522539078975442106423542788756568591467855408382408553291193185913872436208841225697173970945983525762433441481280347267073095988973946288551640697665253280022909335373171912322592251659662483828781073896262013777633044338795549937837706476914073034083128205951091815229110073642507308579820282276373908596113943511888760956906801345851169243249967796462546176381880442440844745894907263034885005676173308947973131884166988356065641058979779068333131042821258186745603686386478048197689095800855972256397909340705366933323634018899563004902813994701591677760332089000234022403809659230861082535195440790226610712069239108787601279605502996064145382535022494841202818660770583946696336876307647640875075143313538435324898349642137831024072627120314207653707058646805602823320946203051266238771092636924654486661

@BoltonBailey your random number is: 10711977686400

Salt: 5DIfdsx1UJPkHmSlTSWF, round: 2567303 (signature 875d9bae472b6d1581d7b25f67a30ca30ad721793f9a2221cc02b7da7f5d48ec9e9f1cc54e43c71100b6b89d070c302315edc086e91c8de1b67ceeb140159390e277a18367aa21ce4a7a4e503836d86b05b7f1245551e730ed0c8810f1119ba5)

@BoltonBailey you asked for a random integer between 1 and 281474976710656, inclusive. Coming up shortly!

Source: GitHub, previous round: 2567301 (latest), offset: 2, selected round: 2567303, salt: 5DIfdsx1UJPkHmSlTSWF.

It's been brought to my attention that the randomness bot has a maximum of 281474976710656, so in the interest of generating a number which is still certifiably random, I'll use the bot to generate a seed for random.org to generate 25 strings of length 10 of digits. If the first digit is 0, I'll use the bot to replace the digit.

@FairlyRandom max=281474976710656

@BoltonBailey *100 strings

bought į¹€20 of NO

Same math as https://manifold.markets/BoltonBailey/will-someone-find-the-prime-factori-f081a7336797#dUveaDmaqJLSpNgCfOQp
Apparently the expectation value for the second largest prime for a random 1000-digit number is about 232 digits, if stack exchange is to be trusted.
So, factoring a random 1000-digit number is (in expectation) about as hard as factoring a 464-digit number that is the product of two 232-digit prime numbers.

It could be that, despite this expectation, there's still a large chance that all the prime factors of a random 1000-digit number are small. I think this is likely not the case, but that's just a guess.