Will at least 5 members abstain/vote present in the ballot electing the next Speaker of the House?
74
416
1.3k
resolved Oct 25
Resolved
NO

Resolves YES if at least 5 members either do not vote or vote "present" in the ballot electing the next Speaker of the House of Representatives, otherwise NO. If there are multiple ballots, only the final deciding ballot counts for this question.

Context: McCarthy won election to the Speakership by convincing 5 Republican holdouts to vote present instead of voting against him.

Unelected or temporary Speakers (e.g. Speaker Pro Tempore) will not count toward resolution

A member not voting for any reason counts, including absence. A vacant seat doesn't count, because it's not a member.

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bought Ṁ10,000 of NO

I count 4 absences.

Made questions about whether each party will have several abstentions.

predicted NO

I'm concerned how absences would count here. Is an absence counted as an abstention?

sold Ṁ51 of NO

@FrederickNorris

either do not vote or vote "present"

Being absent counts as not voting.