Will this simulation of the 2-round Snake Eyes Paradox (Variant Y) output ~1/36?
12
250Ṁ2232
resolved Jul 22
Resolved
YES

Background: The snake eyes paradox market.

Algorithm description:

We start with 3 people willing to play the gruesome snake eyes game. First 1 person will be chosen at random for the initial 1-person group. If that person survives (rolls non-snake-eyes) then we choose the remaining 2 people for the second group and roll for them. You only die by rolling snake eyes.

We repeat the above a [million] times. Each time, we record who was chosen and who died. We then count how many of the [million] times person 1 (WLOG) was chosen to play. (Again, that happens either when person 1 is chosen first, with probability 1/3, or when whoever was chosen first survives.) Call that count C. Finally, we count the number of times, D, that person 1 died.

Output D/C.

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