Manifold Plays Poker: The River (Hand 6)
6
680Ṁ1722
resolved Aug 15
75%31%
Christopher Randles
25%61%
Jason
4%
A
3%
brubsby

The River:

8 of spades, 10 of clubs, 6 of hearts, King of clubs, 2 of spades

Who will win? All players who are at 25%+ when this closes advance to the next round. It will close early at a random predetermined time, after 14:00 PT.

This resolves to the winner(s) of the hand equally.

The Audience's Hand (resurrected! so nice, it was eliminated twice):

King of hearts, 5 of diamonds

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Jason and Christopher both reveal.

Jason has a pair of 10s (the 2 was replaced).

Christopher has two pairs, Kings and 10s. Christopher wins!

(Jason steals 25%)

(benoit blanc voice) by my calculation, Jason, growing covetous of the many cheat related derivative markets, sought out to manipulate them by purchasing many a cheat. however, in doing so he laid bare the fact that he is in possession of the only pair of kings in play. for he did not inquire about the king of diamonds, which is indeed in the game, and might i posit, in his hands! the other two kings belonging to the public and now deceased audience hand. the only way the Randleman could beat him is if he had pocket aces, which may be unlikely, but ultimately possible, as I have only confirmed a single of the aces' presence or absence.

THEREFORE i believe, due to the aforementioned pair cheat, all markets will resolve 75% Jason and 25% Randleman

@brubsby straight, pocket 10s 8s 6s or 2s for 3 of a kind might be other ways? Or maybe I have KD, Jason and I know this of course.

@ChristopherRandles more of a roulette man myself really

@brubsby I did purchase cheats to manipulate some markets. However, I bought the "is there the K of spades" question because I needed a third cheat for myself to ensure the three-cheat market resolved YES. I already thought it likely that Randles had a king based on his bidding behavior at the turn, so I paired to him. That justified keeping myself in the game with a large limit order at 25%, since I'd get that back (and I hope 25% of the prize pot) due to the pairing. Also, in the event I was wrong about Randles, I had NO bets on Fion's markets on whether the leader at the Deal and Flop would win (both of which were me) to recoup some of my losses. Given all of that, I could act fairly confident even though I was pretty sure my hand was not winning.

@Jason i was really just yolo betting because my swap didn't pan out

@Stralor pair with Jason (50 subsidy added)

@brubsby Jason is already paired, sorry

@Stralor I'm happy to refund your subsidy if you'd like

@Stralor oops, no need :)

@Stralor could i, perhaps, use the subsidy on asking if there is an ace of spades in play?

@brubsby answered privately

@Stralor are king of spades and king of diamonds in the game? public answer okay
(100 added to subsidy)

@brubsby

K of spades: No

K of diamonds: Yes

@Stralor very suspicious....

Two cheats have been claimed!

@brubsby replaces a 7 of clubs

@A replaces a 4 of spades

no more card swaps are available!

CHEAT 3: Is K of spades in play? Pls answer privately

@Jason answer sent!

CHEAT 2: Pair w/ Randleman pls

@Jason Randles* (sry autocorrect)

@Jason paired! did you want a second cheat for your other 50?

@Jason "Randleman" I'm here for it 😂

@Stralor Presumably you knew I was going for the three-cheats market :)

@Jason Change 2D, resurrect audience, pair Randleman, Ask KS in play =4?

@ChristopherRandles The 3-cheat market rules say the resurrect audience counts as for audience, not me. Unsure about other cheat count markets.

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