At the close of this market, I will look at each position in the market, take the number of digits in it (so, a $1,000 mana position is four digits) and add up all the digit counts.
If that number is divisible evenly, without remainder, by the number of participants - the market resolves YES. Otherwise NO. I will place an initial stake in the market because everything divides by one and no one wants a divide by zero error!
Example:
A has Ṁ 327,789 in YES, B has Ṁ 2,476 in YES, C has Ṁ 5 in NO.
6 + 4 + 1 = 11, 11 / 3 = 3 remainder 2, market resolves NO.
1,000🏅 Top traders
| # | Name | Total profit |
|---|---|---|
| 1 | Ṁ125 | |
| 2 | Ṁ61 | |
| 3 | Ṁ56 | |
| 4 | Ṁ42 | |
| 5 | Ṁ23 |
@mods Can someone resolve this NO?
There are 25 traders with positions, and a total of 52 digits across all positions.
@MattCWilson If we do, it's not going to make the average 3 digits. the market is mathematically equivalent to if the average number of digits is an integer, i should have made that clear in the previous post
Just to help demonstrate how this market will evaluate: at the present moment, YES has it with 30 digits of positions divided by 15 positions.
(A couple single digit NO positions couldn’t fit in my screenshot sorry 😞)
Steal of a buy for new YESes right now (provided you buy in for 2 or 18 digits worth of mana!)