
In the Manifold MTG tournament, will anyone go 5-0 in the Swiss?
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250Ṁ3702resolved Apr 18
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Interesting question. @IsaacKing, I assume the Swiss format is going to pair up top-record players vs each other? That means the number of candidates for a 5-0 record will be cut in half each round, more or less. So after 4 rounds, you are guaranteed to have only 1 left with a perfect record? 14 -> 7 -> 3/4 -> 1/2 -> 1 -> 0/1 Then the last round is the only thing that matters to this question, if I understand the Swiss format correctly.