What will this market's trading volume be? [Add answers!]

Basic

Ṁ1.1m

Oct 20

ALL

30%

10 or less away from a prime number

15%

a multiple of seven

50%

an even number

99%

> (number of traders) * 5000

99%

> (number of traders) * 1000

a valid NANP phone number (with or without leading country code) that a bot/machine answers to when called

a valid NANP phone number (with or without leading country code) that a human answers to when called

17%

sin(sqrt((trading volume))) > 0.8

50%

sin(sqrt((trading volume))) > 0

Resolves according to this market's trading volume at market close.

Answers that become guaranteed/impossible may resolve early.

This question is managed and resolved by Manifold.

Get

1,000

and

1.00

19 Comments

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@Robincvgr Some answers can resolve early.

Within a factor of 5 of 5555, Within factor 4 of 4444, Within factor 2 of 22222,
In the range Pi^e^2 to e^Pi^2,
8! to 9! (so 40320 to 362880) are guaranteed NO.

≥Ṁ1,000,000 is a YES.

@bagelfan thank you for pointing these out

@Robincvgr Israel-Hezbollah also resolves, since that market resolved and this one already has more :)

opened a Ṁ1,000 ≥Ṁ1,000,000 NO at 99.0% order

oops misclick

opened a Ṁ13,500 ≥Ṁ1,000,000 YES at 90% order

you can have it back after a modest transaction fee

opened a Ṁ150 ≥Ṁ1,000,000 NO at 99.0% order

@jacksonpolack I think I'm ok, you can inflate trading volume for basically nothing rn

opened a Ṁ14,700 ≥Ṁ1,000,000 YES at 98% order

@bagelfan how about 98

bought Ṁ200 Within factor 5 of 5555 YES

@jacksonpolack I'm good.

boughtṀ2510 or less away from... NO

@Hyperlincoln do you want to bet a larger amount about this?

@Robincvgr I would greatly appreciate if you would promise not to manipulate the market e.g. by vastly inflating the trading volume single-handedly

@TheAllMemeingEye Now that creator fees are gone, and I've done my best to minimize ambiguity in the answers I added, I don't see why I have much reason to act differently in this market than any other trader

@Robincvgr do you at least promise not to cheat using alt accounts?

@TheAllMemeingEye Sure, I don't even have any alt accounts

@Robincvgr thanks

In the range Pi^e^2 to e^Pi^2

@ChristopherRandles could you clarify the order of operations here? E.g. by adding brackets

@TheAllMemeingEye
=exp(1)^pi()^2 in google docs seems to be calculated as =exp(1)^(pi()^2) = 19333.68 That is what I intended anyway.

I tried to edit in brackets but only allowed within 1 hour of creation.

@ChristopherRandles just to be clear, do I understand correctly that this is therefore pi^(e^2) < x < e^(pi^2)?

bought Ṁ76 Within factor 10 of ... NO

@TheAllMemeingEye yes that is correct.

I make the range 4715 to 19333

bought Ṁ5 > (number of traders... NO

@mods unrank please

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