We only care about the integer part cutting off any fraction without rounding.. We are only referring to the closing price.
This is for a timespan of 10 days. If there is a holiday or other day without a unique closing price in the interval due to the market not having been open, we will extend the deadline to get another day until there are 10 days included.
If after the week, from within the ten closing prices, every decimal digit appears at least once, this resolves YES. Otherwise NO. It can resolve early.
Example prices:
day 1: closes at 127.45 -> 1,2,7 seen
day 2: closes at 139.9907 -> 1,2,3,7,9 seen
Etc
If all seen by the end, YES, otherwise NO
Related questions
Day seven: 4273
We are at {0, 2, 3, 4, 5, 7}, no change
We just need {1,6,8,9} in three days.
We could hit 4289, 4298, 4268, 4198, or many other nice numbers to improve the situation!
@StrayClimb Manifold's YES bias in action. This is a perfectly good situation imo
/StrayClimb/will-every-digit-09-appear-in-the-s-22adc1b1b3db
/StrayClimb/will-every-digit-09-appear-in-the-s-7fb9aa0b9f03
Did you know it's technically impossible to lose more than N coin flips in a row, for some N?
day five: 4320
We are at {0, 2, 3, 4, 5}, no change
Well, half done in the first half of the timespan... that's good... right?
Day four: 4330
We are at {0, 2, 3, 4, 5}, no change from yesterday.
6 days left to get just 5 digits! This should be doable right?
Is anybody cross-playing these with the markets about huge spikes / drops? If one of those happens you might get some unexpected digits for free!
@StrayClimb I give it about 19% (two random numbers/d, 8 days to go). Will geht my loses back via my new No Payout.
@Willi yes... What gets me is that it's not actually random, particularly the tens digit. I was surprised by the big drop yesterday.
Day two result: 4443
Wow so close to 4444!
We are at {3,4,5} no change from yesterday with eight days to go.
Interesting market. Confirming, this is not counting any of the "change" i.e. if it closes at $123.45 the .45 would not be included, correct?
@dieselbaby1337 correct. Just the integer part of digits excluding leading zero
It's going to be so exciting to see the first day changes. Imagine it closes at 4444...
We'll almost certainly have a 4 from the thousands digit; the hundreds digit will probably cover one or two more digits, leaving seven or eight digits uncovered; let's pretend the tens and ones digits are totally random; then the probability of never getting the digit 0 in 20 tries is (0.9)^20, which is about 12%, so 88% chance that 0 is covered; repeating this for all the remaining digits, 88% to the power 8 is 36%, or to the power 7 is 41%; though the probability of there being at least one 1 is a bit less if there's at least one 0, and so on
@StevenK ive been thinking about making partly overlapping markets like for different day intervals too. The arbitrage possibilities could get pretty interesting.
@StrayClimb description refers to the last digit several times. But for this market the last digit isn't special, right?
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