Repeated random reduction of a number, and it's still 10 or more?
3
Ṁ100Ṁ78Apr 26
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On the resolution date I will:
Set the integer variable "n" to 320.
Then use fairlyrandom to generate a random integer up to "n", and "n" will be assigned the value of this response. This step (step 2) will be repeated until 5 calls to fairlyrandom have been made.
If "n" is now at least 10, I'll resolve to "Yes", otherwise to "No".
This question is managed and resolved by Manifold.
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@4fa Yes :) It cannot grow, so less than 10 on the 3rd lets say, guarantees less than 10 by the 5th. If fairlyrandom wont play ball in the eventuality of "fairlyrandom 1" then I'll just pretend it answered "1".