Will the total number of games played in the match between Elena Rybakina and Kaja Juvan exceed 15?
4
Ṁ100Ṁ216
resolved Jan 20
Resolved
YES

Resolution criteria

This match is the 1st round of the Australian Open, which uses best-of-3 sets for all WTA matches. The market resolves YES if the total number of games played across all sets exceeds 15, and NO if it is 15 or fewer.

A set is won by the first player to reach six games with at least a two-game advantage, and if the set reaches 6–6, a tiebreak is used to decide the winner. The minimum games in a best-of-3 match is 12 (two sets of 6-4 or 6-3), while a competitive match with tiebreaks can easily exceed 15 games. Resolution will be determined by the official match score from the Australian Open.

Background

Elena Rybakina is ranked World No. 5 and will face Slovenian Kaja Juvan (ranked 97). Rybakina and Juvan have played once before, with Rybakina winning 6-2 6-1 at the Australian Open. Predictions favor Rybakina to win in 2 sets.

Considerations

A straight-set victory (e.g., 6-4, 6-3) would result in 12 total games, resolving NO. However, if either set goes to a tiebreak or extends to 7 games, the total will likely exceed 15 games. For example, a 7-6, 6-4 scoreline would yield 17 games total.

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