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Related questions
🏅 Top traders
# | Name | Total profit |
---|---|---|
1 | Ṁ87 | |
2 | Ṁ55 | |
3 | Ṁ13 | |
4 | Ṁ10 | |
5 | Ṁ5 |
Will this market stump everyone?
The last encoded market I made turned out to be too easy - it was solved in less than nine hours. Maybe this one will take a little longer for someone to figure out. This market resolves NO if someone posts the full, decoded title and description in the comments before close. Otherwise it resolves YES, and I will post them after it closes. As with the previous market, I won't reveal the answer to anyone beforehand, but I might post clues.
The title and description are both encoded in a method very similar to the previous market, except that I used the product of the ASCII values instead of their sum. However, in order for the encoding to be reversible, I needed the modulus to be prime, since prime numbers are the only moduli for which the residue classes form a field, i.e., they are the only numbers p for which division mod p is well-defined for all nonzero divisors. I also needed to ensure that each printable character corresponds to a nonzero value mod p (otherwise, using that character would multiply the running product by zero, causing every character afterwards in the encoding to be the same), and that every nonzero residue class corresponds to a character. Luckily, 97 is prime, and there are 95 printable ASCII characters, so I just needed one more character to fill out the final residue class. I ended up using the newline character ('\n' in Python).
Thus, the final code was this: Each character in the title or description is assigned a value, equal to its ascii value value minus 31 for the 95 printable ascii characters, or to 96 for newline. The nth character in the encoded text is the one whose value is the product of the values of the first n characters in the original text, mod 97.
@JosephNoonan Damn, I did consider products, but the large number of repeated character pairs threw me off. Should have occurred to me that it just meant space was mapped to 1, which is a priori very plausible.
Here's the description on pastebin: https://pastebin.com/t9YpFwjy
To be sure I'm getting the precise ciphertext, could you post a .txt file version? Just in case anything gets messed up from manifold processing or copying over from this page.
@jskf Good idea. I was worried that that might happen and make this artificially difficult, because I had to manually fix some formatting after pasting it into Manifold, and I know that you have to do the same when copying it from Manifold and pasting it somewhere else as well.
Here's a link to the text files of the title and description: https://filebin.net/i2auck047taypilo
If anybody else needs a link after this one expires, just comment here and ask for one.
@JosephNoonan Just to confirm, are those newlines definitely meant to be in the ciphertext? They seem like unusual outliers when the rest of the characters are in the range (32, 126).